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-4x^2+36x-72=0
a = -4; b = 36; c = -72;
Δ = b2-4ac
Δ = 362-4·(-4)·(-72)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-12}{2*-4}=\frac{-48}{-8} =+6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+12}{2*-4}=\frac{-24}{-8} =+3 $
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